12114343021231 has 8 divisors (see below), whose sum is σ = 13215996572544. Its totient is φ = 11012747743320.

The previous prime is 12114343021229. The next prime is 12114343021303. The reversal of 12114343021231 is 13212034341121.

12114343021231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12114343021231 - 2¹ = 12114343021229 is a prime.

It is a super-3 number, since 3×12114343021231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12114343021231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114343021631) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14133105 + ... + 14965738.

It is an arithmetic number, because the mean of its divisors is an integer number (1651999571568).

Almost surely, 2^{12114343021231} is an apocalyptic number.

12114343021231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

12114343021231 is a deficient number, since it is larger than the sum of its proper divisors (1101653551313).

12114343021231 is a wasteful number, since it uses less digits than its factorization.

12114343021231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29136701.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 12114343021231 its reverse (13212034341121), we get a palindrome (25326377362352).

The spelling of 12114343021231 in words is "twelve trillion, one hundred fourteen billion, three hundred forty-three million, twenty-one thousand, two hundred thirty-one".