12114420203832 has 64 divisors (see below), whose sum is σ = 30395276624160. Its totient is φ = 4023577958400.

The previous prime is 12114420203827. The next prime is 12114420203843. The reversal of 12114420203832 is 23830202441121.

It is a happy number.

It is a super-3 number, since 3×12114420203832³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12114420203793 and 12114420203802.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 250724508 + ... + 250772820.

Almost surely, 2^{12114420203832} is an apocalyptic number.

12114420203832 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12114420203832 is an abundant number, since it is smaller than the sum of its proper divisors (18280856420328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12114420203832 is a wasteful number, since it uses less digits than its factorization.

12114420203832 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85784 (or 85780 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 12114420203832 its reverse (23830202441121), we get a palindrome (35944622644953).

The spelling of 12114420203832 in words is "twelve trillion, one hundred fourteen billion, four hundred twenty million, two hundred three thousand, eight hundred thirty-two".