12114430241 has 2 divisors, whose sum is σ = 12114430242. Its totient is φ = 12114430240.

The previous prime is 12114430219. The next prime is 12114430243. The reversal of 12114430241 is 14203441121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11033401600 + 1081028641 = 105040^2 + 32879^2 .

It is an emirp because it is prime and its reverse (14203441121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12114430241 is a prime.

It is a super-3 number, since 3×12114430241³ (a number of 31 digits) contains 333 as substring.

Together with 12114430243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12114430243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057215120 + 6057215121.

It is an arithmetic number, because the mean of its divisors is an integer number (6057215121).

Almost surely, 2^12114430241 is an apocalyptic number.

It is an amenable number.

12114430241 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114430241 is an equidigital number, since it uses as much as digits as its factorization.

12114430241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 12114430241 its reverse (14203441121), we get a palindrome (26317871362).

The spelling of 12114430241 in words is "twelve billion, one hundred fourteen million, four hundred thirty thousand, two hundred forty-one".