12114503 has 4 divisors (see below), whose sum is σ = 12441960. Its totient is φ = 11787048.

The previous prime is 12114497. The next prime is 12114559. The reversal of 12114503 is 30541121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30541121 = 13 ⋅2349317.

It is a cyclic number.

It is not a de Polignac number, because 12114503 - 2⁶ = 12114439 is a prime.

It is a super-3 number, since 3×12114503³ (a number of 22 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163673 + ... + 163746.

It is an arithmetic number, because the mean of its divisors is an integer number (3110490).

Almost surely, 2^12114503 is an apocalyptic number.

12114503 is a deficient number, since it is larger than the sum of its proper divisors (327457).

12114503 is an equidigital number, since it uses as much as digits as its factorization.

12114503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327456.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 12114503 is about 3480.5894615711. The cubic root of 12114503 is about 229.6687291461.

Adding to 12114503 its reverse (30541121), we get a palindrome (42655624).

The spelling of 12114503 in words is "twelve million, one hundred fourteen thousand, five hundred three".