Base | Representation |
---|---|
bin | 11011100010111001010110… |
… | …101100010100101010110111 |
3 | 120212221101012101120101022211 |
4 | 123202321112230110222313 |
5 | 111334321034303314201 |
6 | 1105353214453434251 |
7 | 34342313342512210 |
oct | 3342712654245267 |
9 | 525841171511284 |
10 | 121145302010551 |
11 | 35667485808245 |
12 | 1170693063b987 |
13 | 5279c50869040 |
14 | 21cb66cd40407 |
15 | e014022ee651 |
hex | 6e2e56b14ab7 |
121145302010551 has 64 divisors (see below), whose sum is σ = 155803253760000. Its totient is φ = 91555029853056.
The previous prime is 121145302010543. The next prime is 121145302010567. The reversal of 121145302010551 is 155010203541121.
It is not a de Polignac number, because 121145302010551 - 23 = 121145302010543 is a prime.
It is a super-3 number, since 3×1211453020105513 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121145302010581) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4477066260 + ... + 4477093318.
It is an arithmetic number, because the mean of its divisors is an integer number (2434425840000).
Almost surely, 2121145302010551 is an apocalyptic number.
121145302010551 is a deficient number, since it is larger than the sum of its proper divisors (34657951749449).
121145302010551 is a wasteful number, since it uses less digits than its factorization.
121145302010551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30028.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 121145302010551 its reverse (155010203541121), we get a palindrome (276155505551672).
The spelling of 121145302010551 in words is "one hundred twenty-one trillion, one hundred forty-five billion, three hundred two million, ten thousand, five hundred fifty-one".
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