Base | Representation |
---|---|
bin | 11011100010111101101111… |
… | …011000111001000100000000 |
3 | 120212221211100120221210210002 |
4 | 123202331233120321010000 |
5 | 111334410210344030212 |
6 | 1105355314042255132 |
7 | 34342541135110142 |
oct | 3342755730710400 |
9 | 525854316853702 |
10 | 121150011314432 |
11 | 35669482015a21 |
12 | 117078257b74a8 |
13 | 527a521406899 |
14 | 21cb998570c92 |
15 | e015ca983ac2 |
hex | 6e2f6f639100 |
121150011314432 has 72 divisors (see below), whose sum is σ = 245442219460032. Its totient is φ = 59669421926400.
The previous prime is 121150011314407. The next prime is 121150011314443. The reversal of 121150011314432 is 234413110051121.
It is a junction number, because it is equal to n+sod(n) for n = 121150011314395 and 121150011314404.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1081051682 + ... + 1081163742.
Almost surely, 2121150011314432 is an apocalyptic number.
It is an amenable number.
121150011314432 is an abundant number, since it is smaller than the sum of its proper divisors (124292208145600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121150011314432 is an equidigital number, since it uses as much as digits as its factorization.
121150011314432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175175 (or 175161 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 121150011314432 its reverse (234413110051121), we get a palindrome (355563121365553).
The spelling of 121150011314432 in words is "one hundred twenty-one trillion, one hundred fifty billion, eleven million, three hundred fourteen thousand, four hundred thirty-two".
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