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12115031553139 = 72320916751771
BaseRepresentation
bin1011000001001100000000…
…1001101111010001110011
31120220012000101020110111111
42300103000021233101303
53041443041034200024
641433322455254151
72360165530045054
oct260230011572163
946805011213444
1012115031553139
113950a57523299
121437b8367a357
1369b59a445268
142dc52911872b
15160216b03a94
hexb04c026f473

12115031553139 has 4 divisors (see below), whose sum is σ = 12115049028120. Its totient is φ = 12115014078160.

The previous prime is 12115031553137. The next prime is 12115031553193. The reversal of 12115031553139 is 93135513051121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12115031553139 - 21 = 12115031553137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12115031553133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7652677 + ... + 9099094.

It is an arithmetic number, because the mean of its divisors is an integer number (3028762257030).

Almost surely, 212115031553139 is an apocalyptic number.

12115031553139 is a deficient number, since it is larger than the sum of its proper divisors (17474981).

12115031553139 is an equidigital number, since it uses as much as digits as its factorization.

12115031553139 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17474980.

The product of its (nonzero) digits is 60750, while the sum is 40.

The spelling of 12115031553139 in words is "twelve trillion, one hundred fifteen billion, thirty-one million, five hundred fifty-three thousand, one hundred thirty-nine".

Divisors: 1 723209 16751771 12115031553139