Base | Representation |
---|---|
bin | 1011000001001100000000… |
… | …1001101111010001110100 |
3 | 1120220012000101020110111112 |
4 | 2300103000021233101310 |
5 | 3041443041034200030 |
6 | 41433322455254152 |
7 | 2360165530045055 |
oct | 260230011572164 |
9 | 46805011213445 |
10 | 12115031553140 |
11 | 3950a5752329a |
12 | 1437b8367a358 |
13 | 69b59a445269 |
14 | 2dc52911872c |
15 | 160216b03a95 |
hex | b04c026f474 |
12115031553140 has 48 divisors (see below), whose sum is σ = 26443985645952. Its totient is φ = 4658231581056.
The previous prime is 12115031553137. The next prime is 12115031553193. The reversal of 12115031553140 is 4135513051121.
It is a junction number, because it is equal to n+sod(n) for n = 12115031553097 and 12115031553106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 98563064 + ... + 98685903.
It is an arithmetic number, because the mean of its divisors is an integer number (550916367624).
Almost surely, 212115031553140 is an apocalyptic number.
12115031553140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12115031553140 is an abundant number, since it is smaller than the sum of its proper divisors (14328954092812).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12115031553140 is a wasteful number, since it uses less digits than its factorization.
12115031553140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197249096 (or 197249094 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 32.
The spelling of 12115031553140 in words is "twelve trillion, one hundred fifteen billion, thirty-one million, five hundred fifty-three thousand, one hundred forty".
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