Base | Representation |
---|---|
bin | 1011000001001101100101… |
… | …1001110111001101000111 |
3 | 1120220020002220102110212212 |
4 | 2300103121121313031013 |
5 | 3041444423013212221 |
6 | 41433432511534035 |
7 | 2360212163060135 |
oct | 260233131671507 |
9 | 46806086373785 |
10 | 12115455210311 |
11 | 3951154687192 |
12 | 143808152a31b |
13 | 69b63714a78b |
14 | 2dc5694ba755 |
15 | 16023dddbb5b |
hex | b04d9677347 |
12115455210311 has 2 divisors, whose sum is σ = 12115455210312. Its totient is φ = 12115455210310.
The previous prime is 12115455210293. The next prime is 12115455210343. The reversal of 12115455210311 is 11301255451121.
It is an a-pointer prime, because the next prime (12115455210343) can be obtained adding 12115455210311 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12115455210311 - 222 = 12115451016007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12115455210611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057727605155 + 6057727605156.
It is an arithmetic number, because the mean of its divisors is an integer number (6057727605156).
Almost surely, 212115455210311 is an apocalyptic number.
12115455210311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12115455210311 is an equidigital number, since it uses as much as digits as its factorization.
12115455210311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6000, while the sum is 32.
The spelling of 12115455210311 in words is "twelve trillion, one hundred fifteen billion, four hundred fifty-five million, two hundred ten thousand, three hundred eleven".
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