Base | Representation |
---|---|
bin | 11011100011101100011000… |
… | …111010100100000010111000 |
3 | 120220010121122100220022211110 |
4 | 123203230120322210002320 |
5 | 111341220301113143000 |
6 | 1105434320215400320 |
7 | 34346263316036262 |
oct | 3343543072440270 |
9 | 526117570808743 |
10 | 121200100131000 |
11 | 356887459311a0 |
12 | 117154843830a0 |
13 | 52821746a2997 |
14 | 21d018a9c0b32 |
15 | e02a5d01e850 |
hex | 6e3b18ea40b8 |
121200100131000 has 256 divisors, whose sum is σ = 412604150400000. Its totient is φ = 29375924928000.
The previous prime is 121200100130909. The next prime is 121200100131043. The reversal of 121200100131000 is 131001002121.
It is a super-2 number, since 2×1212001001310002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 164599654 + ... + 165334346.
It is an arithmetic number, because the mean of its divisors is an integer number (1611734962500).
Almost surely, 2121200100131000 is an apocalyptic number.
121200100131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121200100131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (206302075200000).
121200100131000 is an abundant number, since it is smaller than the sum of its proper divisors (291404050269000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121200100131000 is a wasteful number, since it uses less digits than its factorization.
121200100131000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 739727 (or 739713 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 121200100131000 its reverse (131001002121), we get a palindrome (121331101133121).
The spelling of 121200100131000 in words is "one hundred twenty-one trillion, two hundred billion, one hundred million, one hundred thirty-one thousand".
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