12120144341 has 2 divisors, whose sum is σ = 12120144342. Its totient is φ = 12120144340.

The previous prime is 12120144301. The next prime is 12120144343. The reversal of 12120144341 is 14344102121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9706387441 + 2413756900 = 98521^2 + 49130^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12120144341 is a prime.

Together with 12120144343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120144343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060072170 + 6060072171.

It is an arithmetic number, because the mean of its divisors is an integer number (6060072171).

Almost surely, 2^12120144341 is an apocalyptic number.

It is an amenable number.

12120144341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120144341 is an equidigital number, since it uses as much as digits as its factorization.

12120144341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 12120144341 its reverse (14344102121), we get a palindrome (26464246462).

The spelling of 12120144341 in words is "twelve billion, one hundred twenty million, one hundred forty-four thousand, three hundred forty-one".