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12120320113 = 111101847283
BaseRepresentation
bin10110100100110110…
…10110100001110001
31011021200112001111221
423102123112201301
5144310300220423
65322404305041
7606232010146
oct132233264161
934250461457
1012120320113
11515a671990
1224230a2181
1311b2071365
1482d9bc3cd
154ae0dae5d
hex2d26d6871

12120320113 has 4 divisors (see below), whose sum is σ = 13222167408. Its totient is φ = 11018472820.

The previous prime is 12120320111. The next prime is 12120320131. The reversal of 12120320113 is 31102302121.

12120320113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31102302121 = 112827482011.

It is a cyclic number.

It is not a de Polignac number, because 12120320113 - 21 = 12120320111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12120320111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550923631 + ... + 550923652.

It is an arithmetic number, because the mean of its divisors is an integer number (3305541852).

Almost surely, 212120320113 is an apocalyptic number.

It is an amenable number.

12120320113 is a deficient number, since it is larger than the sum of its proper divisors (1101847295).

12120320113 is a wasteful number, since it uses less digits than its factorization.

12120320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1101847294.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12120320113 its reverse (31102302121), we get a palindrome (43222622234).

It can be divided in two parts, 12120 and 320113, that added together give a palindrome (332233).

The spelling of 12120320113 in words is "twelve billion, one hundred twenty million, three hundred twenty thousand, one hundred thirteen".

Divisors: 1 11 1101847283 12120320113