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1212044492117 is a prime number
BaseRepresentation
bin10001101000110011011…
…110110011110101010101
311021212111110112201001002
4101220303132303311111
5124324231342221432
62324445555513045
7153365410124264
oct21506336636525
94255443481032
101212044492117
11428030577308
12176a9b2b8785
138a3aba29914
14429400085db
15217dc2e8e62
hex11a337b3d55

1212044492117 has 2 divisors, whose sum is σ = 1212044492118. Its totient is φ = 1212044492116.

The previous prime is 1212044491951. The next prime is 1212044492119. The reversal of 1212044492117 is 7112944402121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 743304346801 + 468740145316 = 862151^2 + 684646^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212044492117 - 236 = 1143325015381 is a prime.

Together with 1212044492119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212044492119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606022246058 + 606022246059.

It is an arithmetic number, because the mean of its divisors is an integer number (606022246059).

Almost surely, 21212044492117 is an apocalyptic number.

It is an amenable number.

1212044492117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212044492117 is an equidigital number, since it uses as much as digits as its factorization.

1212044492117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 38.

Adding to 1212044492117 its reverse (7112944402121), we get a palindrome (8324988894238).

The spelling of 1212044492117 in words is "one trillion, two hundred twelve billion, forty-four million, four hundred ninety-two thousand, one hundred seventeen".