Base | Representation |
---|---|
bin | 10001101000111100110… |
… | …111101100011001110111 |
3 | 11021212220102221110021022 |
4 | 101220330313230121313 |
5 | 124330042203311411 |
6 | 2324513344011355 |
7 | 153402332035622 |
oct | 21507467543167 |
9 | 4255812843238 |
10 | 1212202010231 |
11 | 428101483a73 |
12 | 176b24000b5b |
13 | 8a40555b7c4 |
14 | 42956cccdb9 |
15 | 217eb060edb |
hex | 11a3cdec677 |
1212202010231 has 2 divisors, whose sum is σ = 1212202010232. Its totient is φ = 1212202010230.
The previous prime is 1212202010209. The next prime is 1212202010233. The reversal of 1212202010231 is 1320102022121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1212202010231 - 230 = 1211128268407 is a prime.
It is a super-2 number, since 2×12122020102312 (a number of 25 digits) contains 22 as substring.
Together with 1212202010233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212202010233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606101005115 + 606101005116.
It is an arithmetic number, because the mean of its divisors is an integer number (606101005116).
Almost surely, 21212202010231 is an apocalyptic number.
1212202010231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212202010231 is an equidigital number, since it uses as much as digits as its factorization.
1212202010231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1212202010231 its reverse (1320102022121), we get a palindrome (2532304032352).
The spelling of 1212202010231 in words is "one trillion, two hundred twelve billion, two hundred two million, ten thousand, two hundred thirty-one".
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