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12123310303 = 13932562331
BaseRepresentation
bin10110100101001101…
…10000100011011111
31011021220010222021201
423102212300203133
5144312031412203
65322552340331
7606266302666
oct132246604337
934256128251
1012123310303
115161324515
1224240a46a7
1311b287a3c0
14830159ddd
154ae4cbe1d
hex2d29b08df

12123310303 has 4 divisors (see below), whose sum is σ = 13055872648. Its totient is φ = 11190747960.

The previous prime is 12123310267. The next prime is 12123310313. The reversal of 12123310303 is 30301332121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12123310303 - 213 = 12123302111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12123310313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466281153 + ... + 466281178.

It is an arithmetic number, because the mean of its divisors is an integer number (3263968162).

Almost surely, 212123310303 is an apocalyptic number.

12123310303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12123310303 is a deficient number, since it is larger than the sum of its proper divisors (932562345).

12123310303 is an equidigital number, since it uses as much as digits as its factorization.

12123310303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 932562344.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 12123310303 its reverse (30301332121), we get a palindrome (42424642424).

The spelling of 12123310303 in words is "twelve billion, one hundred twenty-three million, three hundred ten thousand, three hundred three".

Divisors: 1 13 932562331 12123310303