Base | Representation |
---|---|
bin | 10001101001101100011… |
… | …011110101000011110111 |
3 | 11021221222001112010221020 |
4 | 101221230123311003313 |
5 | 124333211000341043 |
6 | 2325124451552223 |
7 | 153431161660512 |
oct | 21515433650367 |
9 | 4257861463836 |
10 | 1213000012023 |
11 | 42848097a588 |
12 | 1771072bb673 |
13 | 8a501992007 |
14 | 429d0c97d79 |
15 | 21846140e83 |
hex | 11a6c6f50f7 |
1213000012023 has 4 divisors (see below), whose sum is σ = 1617333349368. Its totient is φ = 808666674680.
The previous prime is 1213000012013. The next prime is 1213000012073. The reversal of 1213000012023 is 3202100003121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213000012023 - 28 = 1213000011767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1213000011993 and 1213000012011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213000012013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202166668668 + ... + 202166668673.
It is an arithmetic number, because the mean of its divisors is an integer number (404333337342).
Almost surely, 21213000012023 is an apocalyptic number.
1213000012023 is a deficient number, since it is larger than the sum of its proper divisors (404333337345).
1213000012023 is an equidigital number, since it uses as much as digits as its factorization.
1213000012023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 404333337344.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1213000012023 its reverse (3202100003121), we get a palindrome (4415100015144).
The spelling of 1213000012023 in words is "one trillion, two hundred thirteen billion, twelve thousand, twenty-three".
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