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12130000303 = 82333894349
BaseRepresentation
bin10110100110000000…
…10001110110101111
31011022100201212020111
423103000101312233
5144320240002203
65323352000451
7606410205241
oct132300216657
934270655214
1012130000303
115165083843
122426390127
1311b4080495
14830dbc091
154aed9e26d
hex2d3011daf

12130000303 has 8 divisors (see below), whose sum is σ = 12151116000. Its totient is φ = 12108901728.

The previous prime is 12130000241. The next prime is 12130000319. The reversal of 12130000303 is 30300003121.

12130000303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12130000303 - 225 = 12096445871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12130010303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2786973 + ... + 2791321.

It is an arithmetic number, because the mean of its divisors is an integer number (1518889500).

Almost surely, 212130000303 is an apocalyptic number.

12130000303 is a deficient number, since it is larger than the sum of its proper divisors (21115697).

12130000303 is an equidigital number, since it uses as much as digits as its factorization.

12130000303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8561.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 12130000303 its reverse (30300003121), we get a palindrome (42430003424).

The spelling of 12130000303 in words is "twelve billion, one hundred thirty million, three hundred three", and thus it is an aban number.

Divisors: 1 823 3389 4349 2789147 3579227 14738761 12130000303