Base | Representation |
---|---|
bin | 1011000010000011110110… |
… | …0010111001101011011110 |
3 | 1120221121200222000210001001 |
4 | 2300200331202321223132 |
5 | 3042214240133000410 |
6 | 41444242050140514 |
7 | 2361236131343266 |
oct | 260407542715336 |
9 | 46847628023031 |
10 | 12130020203230 |
11 | 39573491a2a16 |
12 | 143aa6728173a |
13 | 69cb18819197 |
14 | 2dd14ba267a6 |
15 | 1607e292533a |
hex | b083d8b9ade |
12130020203230 has 32 divisors (see below), whose sum is σ = 23118603431904. Its totient is φ = 4566553967616.
The previous prime is 12130020203131. The next prime is 12130020203251. The reversal of 12130020203230 is 3230202003121.
It is a junction number, because it is equal to n+sod(n) for n = 12130020203198 and 12130020203207.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23250114 + ... + 23766106.
It is an arithmetic number, because the mean of its divisors is an integer number (722456357247).
Almost surely, 212130020203230 is an apocalyptic number.
12130020203230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12130020203230 is a deficient number, since it is larger than the sum of its proper divisors (10988583228674).
12130020203230 is a wasteful number, since it uses less digits than its factorization.
12130020203230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 654300.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 12130020203230 its reverse (3230202003121), we get a palindrome (15360222206351).
The spelling of 12130020203230 in words is "twelve trillion, one hundred thirty billion, twenty million, two hundred three thousand, two hundred thirty".
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