1213003131223 has 4 divisors (see below), whose sum is σ = 1306311064408. Its totient is φ = 1119695198040.

The previous prime is 1213003131217. The next prime is 1213003131257. The reversal of 1213003131223 is 3221313003121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213003131223 - 2²¹ = 1213001034071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213003131194 and 1213003131203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213003431223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46653966573 + ... + 46653966598.

It is an arithmetic number, because the mean of its divisors is an integer number (326577766102).

Almost surely, 2^{1213003131223} is an apocalyptic number.

1213003131223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1213003131223 is a deficient number, since it is larger than the sum of its proper divisors (93307933185).

1213003131223 is an equidigital number, since it uses as much as digits as its factorization.

1213003131223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93307933184.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1213003131223 its reverse (3221313003121), we get a palindrome (4434316134344).

It can be divided in two parts, 121300 and 3131223, that added together give a palindrome (3252523).

The spelling of 1213003131223 in words is "one trillion, two hundred thirteen billion, three million, one hundred thirty-one thousand, two hundred twenty-three".