12130040983 has 8 divisors (see below), whose sum is σ = 12247750800. Its totient is φ = 12012411840.

The previous prime is 12130040977. The next prime is 12130040999. The reversal of 12130040983 is 38904003121.

12130040983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12130040983 - 2⁹ = 12130040471 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12130040963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 307653 + ... + 344833.

It is an arithmetic number, because the mean of its divisors is an integer number (1530968850).

Almost surely, 2^12130040983 is an apocalyptic number.

12130040983 is a deficient number, since it is larger than the sum of its proper divisors (117709817).

12130040983 is a wasteful number, since it uses less digits than its factorization.

12130040983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40337.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 12130040983 in words is "twelve billion, one hundred thirty million, forty thousand, nine hundred eighty-three".