Base | Representation |
---|---|
bin | 10110100110000000… |
… | …11011110010011011 |
3 | 1011022100210221001022 |
4 | 23103000123302123 |
5 | 144320242302422 |
6 | 5323352513055 |
7 | 606410434661 |
oct | 132300336233 |
9 | 34270727038 |
10 | 12130040987 |
11 | 5165101369 |
12 | 24263ab78b |
13 | 11b4095b5c |
14 | 830dccc31 |
15 | 4aedab342 |
hex | 2d301bc9b |
12130040987 has 4 divisors (see below), whose sum is σ = 12130263600. Its totient is φ = 12129818376.
The previous prime is 12130040977. The next prime is 12130040999. The reversal of 12130040987 is 78904003121.
12130040987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 78904003121 = 41 ⋅1924487881.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12130040987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12130040977) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31514 + ... + 158912.
It is an arithmetic number, because the mean of its divisors is an integer number (3032565900).
Almost surely, 212130040987 is an apocalyptic number.
12130040987 is a deficient number, since it is larger than the sum of its proper divisors (222613).
12130040987 is an equidigital number, since it uses as much as digits as its factorization.
12130040987 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222612.
The product of its (nonzero) digits is 12096, while the sum is 35.
The spelling of 12130040987 in words is "twelve billion, one hundred thirty million, forty thousand, nine hundred eighty-seven".
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