12130041401 has 2 divisors, whose sum is σ = 12130041402. Its totient is φ = 12130041400.

The previous prime is 12130041397. The next prime is 12130041403. The reversal of 12130041401 is 10414003121.

It is a happy number.

12130041401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11821125625 + 308915776 = 108725^2 + 17576^2 .

It is a cyclic number.

It is not a de Polignac number, because 12130041401 - 2² = 12130041397 is a prime.

Together with 12130041403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12130041401.

It is not a weakly prime, because it can be changed into another prime (12130041403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065020700 + 6065020701.

It is an arithmetic number, because the mean of its divisors is an integer number (6065020701).

Almost surely, 2^12130041401 is an apocalyptic number.

It is an amenable number.

12130041401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12130041401 is an equidigital number, since it uses as much as digits as its factorization.

12130041401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12130041401 its reverse (10414003121), we get a palindrome (22544044522).

The spelling of 12130041401 in words is "twelve billion, one hundred thirty million, forty-one thousand, four hundred one".