Base | Representation |
---|---|
bin | 10110100110001000… |
… | …00110111010100111 |
3 | 1011022102121212011002 |
4 | 23103010012322213 |
5 | 144321014112241 |
6 | 5323425303515 |
7 | 606421555544 |
oct | 132304067247 |
9 | 34272555132 |
10 | 12131004071 |
11 | 51656a99aa |
12 | 2426794b9b |
13 | 11b4342324 |
14 | 83119dbcb |
15 | 4aeeeb89b |
hex | 2d3106ea7 |
12131004071 has 2 divisors, whose sum is σ = 12131004072. Its totient is φ = 12131004070.
The previous prime is 12131004037. The next prime is 12131004077. The reversal of 12131004071 is 17040013121.
It is a happy number.
12131004071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12131004071 - 210 = 12131003047 is a prime.
It is a super-2 number, since 2×121310040712 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12131004077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065502035 + 6065502036.
It is an arithmetic number, because the mean of its divisors is an integer number (6065502036).
Almost surely, 212131004071 is an apocalyptic number.
12131004071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12131004071 is an equidigital number, since it uses as much as digits as its factorization.
12131004071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 12131004071 its reverse (17040013121), we get a palindrome (29171017192).
The spelling of 12131004071 in words is "twelve billion, one hundred thirty-one million, four thousand, seventy-one".
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