Base | Representation |
---|---|
bin | 1011000010001000000001… |
… | …1010111110111111011000 |
3 | 1120221201121011021012001021 |
4 | 2300202000122332333120 |
5 | 3042224034400420204 |
6 | 41444545250332224 |
7 | 2361306004226560 |
oct | 260420032767730 |
9 | 46851534235037 |
10 | 12131142201304 |
11 | 3957874572755 |
12 | 143b11ab8a074 |
13 | 69cc670cc879 |
14 | 2dd216a4dda0 |
15 | 16085b1a4154 |
hex | b08806befd8 |
12131142201304 has 32 divisors (see below), whose sum is σ = 26833862937600. Its totient is φ = 5031349299360.
The previous prime is 12131142201293. The next prime is 12131142201319. The reversal of 12131142201304 is 40310224113121.
It is a super-2 number, since 2×121311422013042 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3493990834 + ... + 3493994305.
It is an arithmetic number, because the mean of its divisors is an integer number (838558216800).
Almost surely, 212131142201304 is an apocalyptic number.
12131142201304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
12131142201304 is an abundant number, since it is smaller than the sum of its proper divisors (14702720736296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12131142201304 is a wasteful number, since it uses less digits than its factorization.
12131142201304 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6987985183 (or 6987985179 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 12131142201304 its reverse (40310224113121), we get a palindrome (52441366314425).
The spelling of 12131142201304 in words is "twelve trillion, one hundred thirty-one billion, one hundred forty-two million, two hundred one thousand, three hundred four".
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