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12133314120000 = 263541719313037
BaseRepresentation
bin1011000010010000000111…
…1000001100100101000000
31120221221012112010002101110
42300210001320030211000
53042243011403320000
641445544554203320
72361413556231213
oct260440170144500
946857175102343
1012133314120000
113958789562387
12143b626423540
136a022207b668
142dd38129b77a
15160936bc5850
hexb0901e0c940

12133314120000 has 560 divisors, whose sum is σ = 44710992152640. Its totient is φ = 2884939776000.

The previous prime is 12133314119977. The next prime is 12133314120043. The reversal of 12133314120000 is 2141333121.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 38603482 + ... + 38916518.

Almost surely, 212133314120000 is an apocalyptic number.

12133314120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12133314120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22355496076320).

12133314120000 is an abundant number, since it is smaller than the sum of its proper divisors (32577678032640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12133314120000 is a wasteful number, since it uses less digits than its factorization.

12133314120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 313108 (or 313083 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12133314120000 its reverse (2141333121), we get a palindrome (12135455453121).

The spelling of 12133314120000 in words is "twelve trillion, one hundred thirty-three billion, three hundred fourteen million, one hundred twenty thousand".