Base | Representation |
---|---|
bin | 1011000010010011110111… |
… | …1111000000111111010100 |
3 | 1120222000210210122011020212 |
4 | 2300210331333000333110 |
5 | 3042302043032244000 |
6 | 41450233020144552 |
7 | 2361450552532526 |
oct | 260447577007724 |
9 | 46860723564225 |
10 | 12134322540500 |
11 | 3959156807656 |
12 | 143b868098158 |
13 | 6a0352c76494 |
14 | 2dd43919ba16 |
15 | 1609954bbc35 |
hex | b093dfc0fd4 |
12134322540500 has 48 divisors (see below), whose sum is σ = 26836820774400. Its totient is φ = 4792289392800.
The previous prime is 12134322540469. The next prime is 12134322540523. The reversal of 12134322540500 is 504522343121.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153559520 + ... + 153638519.
It is an arithmetic number, because the mean of its divisors is an integer number (559100432800).
Almost surely, 212134322540500 is an apocalyptic number.
12134322540500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12134322540500 is an abundant number, since it is smaller than the sum of its proper divisors (14702498233900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12134322540500 is a wasteful number, since it uses less digits than its factorization.
12134322540500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 307198137 (or 307198125 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 12134322540500 its reverse (504522343121), we get a palindrome (12638844883621).
The spelling of 12134322540500 in words is "twelve trillion, one hundred thirty-four billion, three hundred twenty-two million, five hundred forty thousand, five hundred".
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