Base | Representation |
---|---|
bin | 100100001011100… |
… | …0101001011000101 |
3 | 10010121101002201022 |
4 | 1020113011023011 |
5 | 4441241310203 |
6 | 320244240525 |
7 | 42040625624 |
oct | 11027051305 |
9 | 3117332638 |
10 | 1214010053 |
11 | 5733057a3 |
12 | 29a6a0145 |
13 | 16468b359 |
14 | b73396bb |
15 | 718a6a38 |
hex | 485c52c5 |
1214010053 has 4 divisors (see below), whose sum is σ = 1214164140. Its totient is φ = 1213855968.
The previous prime is 1214010029. The next prime is 1214010059. The reversal of 1214010053 is 3500104121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 677717089 + 536292964 = 26033^2 + 23158^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1214010053 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1214010059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64550 + ... + 81207.
It is an arithmetic number, because the mean of its divisors is an integer number (303541035).
Almost surely, 21214010053 is an apocalyptic number.
It is an amenable number.
1214010053 is a deficient number, since it is larger than the sum of its proper divisors (154087).
1214010053 is an equidigital number, since it uses as much as digits as its factorization.
1214010053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154086.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 1214010053 is about 34842.6470435299. The cubic root of 1214010053 is about 1066.7781071827.
Adding to 1214010053 its reverse (3500104121), we get a palindrome (4714114174).
The spelling of 1214010053 in words is "one billion, two hundred fourteen million, ten thousand, fifty-three".
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