Base | Representation |
---|---|
bin | 10001101010101010011… |
… | …101000011111011010111 |
3 | 11022001122120102112220122 |
4 | 101222222131003323113 |
5 | 124342323333204310 |
6 | 2325420021422155 |
7 | 153466025113565 |
oct | 21525235037327 |
9 | 4261576375818 |
10 | 1214040522455 |
11 | 428965252462 |
12 | 17735786a95b |
13 | 8a639414167 |
14 | 42a8d14ca35 |
15 | 218a7675555 |
hex | 11aaa743ed7 |
1214040522455 has 8 divisors (see below), whose sum is σ = 1456865460432. Its totient is φ = 971221195648.
The previous prime is 1214040522427. The next prime is 1214040522503. The reversal of 1214040522455 is 5542250404121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1214040522455 - 212 = 1214040518359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 911129 + ... + 1805058.
It is an arithmetic number, because the mean of its divisors is an integer number (182108182554).
Almost surely, 21214040522455 is an apocalyptic number.
1214040522455 is a deficient number, since it is larger than the sum of its proper divisors (242824937977).
1214040522455 is an equidigital number, since it uses as much as digits as its factorization.
1214040522455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2805585.
The product of its (nonzero) digits is 64000, while the sum is 35.
Adding to 1214040522455 its reverse (5542250404121), we get a palindrome (6756290926576).
The spelling of 1214040522455 in words is "one trillion, two hundred fourteen billion, forty million, five hundred twenty-two thousand, four hundred fifty-five".
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