Base | Representation |
---|---|
bin | 111000100010011000… |
… | …1110110100010001100 |
3 | 102121101110222121202212 |
4 | 1301010301312202030 |
5 | 3442123212102104 |
6 | 131435410005552 |
7 | 11525504333600 |
oct | 1610461664214 |
9 | 377343877685 |
10 | 121413003404 |
11 | 47544525530 |
12 | 1b644b768b8 |
13 | b5abb69764 |
14 | 5c3ac81500 |
15 | 325906836e |
hex | 1c44c7688c |
121413003404 has 72 divisors (see below), whose sum is σ = 269856755280. Its totient is φ = 47264246400.
The previous prime is 121413003401. The next prime is 121413003433. The reversal of 121413003404 is 404300314121.
It is a super-2 number, since 2×1214130034042 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 121413003404.
It is not an unprimeable number, because it can be changed into a prime (121413003401) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2626814 + ... + 2672634.
It is an arithmetic number, because the mean of its divisors is an integer number (3748010490).
Almost surely, 2121413003404 is an apocalyptic number.
121413003404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121413003404, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134928377640).
121413003404 is an abundant number, since it is smaller than the sum of its proper divisors (148443751876).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121413003404 is a wasteful number, since it uses less digits than its factorization.
121413003404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47079 (or 47070 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 121413003404 its reverse (404300314121), we get a palindrome (525713317525).
The spelling of 121413003404 in words is "one hundred twenty-one billion, four hundred thirteen million, three thousand, four hundred four".
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