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121413003404 = 227211122945821
BaseRepresentation
bin111000100010011000…
…1110110100010001100
3102121101110222121202212
41301010301312202030
53442123212102104
6131435410005552
711525504333600
oct1610461664214
9377343877685
10121413003404
1147544525530
121b644b768b8
13b5abb69764
145c3ac81500
15325906836e
hex1c44c7688c

121413003404 has 72 divisors (see below), whose sum is σ = 269856755280. Its totient is φ = 47264246400.

The previous prime is 121413003401. The next prime is 121413003433. The reversal of 121413003404 is 404300314121.

It is a super-2 number, since 2×1214130034042 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121413003404.

It is not an unprimeable number, because it can be changed into a prime (121413003401) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2626814 + ... + 2672634.

It is an arithmetic number, because the mean of its divisors is an integer number (3748010490).

Almost surely, 2121413003404 is an apocalyptic number.

121413003404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121413003404, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134928377640).

121413003404 is an abundant number, since it is smaller than the sum of its proper divisors (148443751876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121413003404 is a wasteful number, since it uses less digits than its factorization.

121413003404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47079 (or 47070 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 121413003404 its reverse (404300314121), we get a palindrome (525713317525).

The spelling of 121413003404 in words is "one hundred twenty-one billion, four hundred thirteen million, three thousand, four hundred four".

Divisors: 1 2 4 7 11 14 22 28 44 49 77 98 154 196 308 539 1078 1229 2156 2458 4916 8603 13519 17206 27038 34412 45821 54076 60221 91642 94633 120442 183284 189266 240884 320747 378532 504031 641494 662431 1008062 1282988 1324862 2016124 2245229 2649724 3528217 4490458 7056434 8980916 14112868 24697519 49395038 56314009 98790076 112628018 225256036 394198063 619454099 788396126 1238908198 1576792252 2477816396 2759386441 4336178693 5518772882 8672357386 11037545764 17344714772 30353250851 60706501702 121413003404