1214211311231 has 4 divisors (see below), whose sum is σ = 1216367992632. Its totient is φ = 1212054629832.

The previous prime is 1214211311221. The next prime is 1214211311233. The reversal of 1214211311231 is 1321131124121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1214211311231 is a prime.

It is a super-2 number, since 2×1214211311231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214211311197 and 1214211311206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214211311233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1078339856 + ... + 1078340981.

It is an arithmetic number, because the mean of its divisors is an integer number (304091998158).

Almost surely, 2^{1214211311231} is an apocalyptic number.

1214211311231 is a deficient number, since it is larger than the sum of its proper divisors (2156681401).

1214211311231 is an equidigital number, since it uses as much as digits as its factorization.

1214211311231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2156681400.

The product of its digits is 288, while the sum is 23.

Adding to 1214211311231 its reverse (1321131124121), we get a palindrome (2535342435352).

The spelling of 1214211311231 in words is "one trillion, two hundred fourteen billion, two hundred eleven million, three hundred eleven thousand, two hundred thirty-one".