12143023411303 has 4 divisors (see below), whose sum is σ = 12143196367960. Its totient is φ = 12142850454648.

The previous prime is 12143023411301. The next prime is 12143023411319. The reversal of 12143023411303 is 30311432034121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12143023411303 - 2¹ = 12143023411301 is a prime.

It is a super-3 number, since 3×12143023411303³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12143023411301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86372973 + ... + 86513446.

It is an arithmetic number, because the mean of its divisors is an integer number (3035799091990).

Almost surely, 2^{12143023411303} is an apocalyptic number.

12143023411303 is a deficient number, since it is larger than the sum of its proper divisors (172956657).

12143023411303 is an equidigital number, since it uses as much as digits as its factorization.

12143023411303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172956656.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 12143023411303 its reverse (30311432034121), we get a palindrome (42454455445424).

The spelling of 12143023411303 in words is "twelve trillion, one hundred forty-three billion, twenty-three million, four hundred eleven thousand, three hundred three".