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12144320044055 = 52428864008811
BaseRepresentation
bin1011000010111001000111…
…1000011101110000010111
31120222222121112200221220022
42300232101320131300113
53042433031412402210
641455005033255355
72362253400106313
oct260562170356027
946888545627808
1012144320044055
113962417076a91
12144179826455b
136a128729b564
142ddb06c70b43
15160d7d035155
hexb0b91e1dc17

12144320044055 has 4 divisors (see below), whose sum is σ = 14573184052872. Its totient is φ = 9715456035240.

The previous prime is 12144320044027. The next prime is 12144320044069. The reversal of 12144320044055 is 55044002344121.

It is a happy number.

12144320044055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12144320044055 - 218 = 12144319781911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214432004401 + ... + 1214432004410.

It is an arithmetic number, because the mean of its divisors is an integer number (3643296013218).

Almost surely, 212144320044055 is an apocalyptic number.

12144320044055 is a deficient number, since it is larger than the sum of its proper divisors (2428864008817).

12144320044055 is an equidigital number, since it uses as much as digits as its factorization.

12144320044055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2428864008816.

The product of its (nonzero) digits is 76800, while the sum is 35.

Adding to 12144320044055 its reverse (55044002344121), we get a palindrome (67188322388176).

The spelling of 12144320044055 in words is "twelve trillion, one hundred forty-four billion, three hundred twenty million, forty-four thousand, fifty-five".

Divisors: 1 5 2428864008811 12144320044055