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121443431 is a prime number
BaseRepresentation
bin1110011110100…
…01010001100111
322110111222001212
413033101101213
5222042142211
620014542035
73003152324
oct717212147
9273458055
10121443431
116260827a
123480791b
131c210c25
14121b3b4b
15a9dd38b
hex73d1467

121443431 has 2 divisors, whose sum is σ = 121443432. Its totient is φ = 121443430.

The previous prime is 121443409. The next prime is 121443433. The reversal of 121443431 is 134344121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121443431 is a prime.

It is a super-2 number, since 2×1214434312 = 29497013866103522, which contains 22 as substring.

Together with 121443433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121443397 and 121443406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121443433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60721715 + 60721716.

It is an arithmetic number, because the mean of its divisors is an integer number (60721716).

Almost surely, 2121443431 is an apocalyptic number.

121443431 is a deficient number, since it is larger than the sum of its proper divisors (1).

121443431 is an equidigital number, since it uses as much as digits as its factorization.

121443431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 23.

The square root of 121443431 is about 11020.1375218279. The cubic root of 121443431 is about 495.2122084376.

Adding to 121443431 its reverse (134344121), we get a palindrome (255787552).

The spelling of 121443431 in words is "one hundred twenty-one million, four hundred forty-three thousand, four hundred thirty-one".