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122002211021027 is a prime number
BaseRepresentation
bin11011101111010111011010…
…011100110010000011100011
3120222222022000212001101120012
4123233113122130302003203
5111442341012010133102
61111251013023435135
734461240344102531
oct3357273234620343
9528868025041505
10122002211021027
11359679355918a7
1211824a19755aab
13530c9b3a80bbc
14221ad1d429151
15e188567ca752
hex6ef5da7320e3

122002211021027 has 2 divisors, whose sum is σ = 122002211021028. Its totient is φ = 122002211021026.

The previous prime is 122002211020979. The next prime is 122002211021029. The reversal of 122002211021027 is 720120112200221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122002211021027 - 240 = 120902699393251 is a prime.

It is a super-2 number, since 2×1220022110210272 (a number of 29 digits) contains 22 as substring.

Together with 122002211021029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 122002211020993 and 122002211021011.

It is not a weakly prime, because it can be changed into another prime (122002211021029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61001105510513 + 61001105510514.

It is an arithmetic number, because the mean of its divisors is an integer number (61001105510514).

Almost surely, 2122002211021027 is an apocalyptic number.

122002211021027 is a deficient number, since it is larger than the sum of its proper divisors (1).

122002211021027 is an equidigital number, since it uses as much as digits as its factorization.

122002211021027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 122002211021027 its reverse (720120112200221), we get a palindrome (842122323221248).

The spelling of 122002211021027 in words is "one hundred twenty-two trillion, two billion, two hundred eleven million, twenty-one thousand, twenty-seven".