Base | Representation |
---|---|
bin | 10110101110011111… |
… | …11011100100101111 |
3 | 1011111022201210121102 |
4 | 23113033323210233 |
5 | 144442002242312 |
6 | 5334414153315 |
7 | 611233410152 |
oct | 132717734457 |
9 | 34438653542 |
10 | 12201212207 |
11 | 51a12a2358 |
12 | 24461b283b |
13 | 11c5a547c2 |
14 | 83a637c99 |
15 | 4b6268ec2 |
hex | 2d73fb92f |
12201212207 has 2 divisors, whose sum is σ = 12201212208. Its totient is φ = 12201212206.
The previous prime is 12201212129. The next prime is 12201212209. The reversal of 12201212207 is 70221210221.
It is a strong prime.
It is an emirp because it is prime and its reverse (70221210221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12201212207 - 214 = 12201195823 is a prime.
Together with 12201212209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12201212209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100606103 + 6100606104.
It is an arithmetic number, because the mean of its divisors is an integer number (6100606104).
Almost surely, 212201212207 is an apocalyptic number.
12201212207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201212207 is an equidigital number, since it uses as much as digits as its factorization.
12201212207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 12201212207 its reverse (70221210221), we get a palindrome (82422422428).
The spelling of 12201212207 in words is "twelve billion, two hundred one million, two hundred twelve thousand, two hundred seven".
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