Base | Representation |
---|---|
bin | 10001110000010100111… |
… | …001100000100100100000 |
3 | 11022122100100112200102222 |
4 | 101300110321200210200 |
5 | 124442302030111000 |
6 | 2332303242330212 |
7 | 154102513126364 |
oct | 21602471404440 |
9 | 4278310480388 |
10 | 1220121332000 |
11 | 4304a575769a |
12 | 1785741b9968 |
13 | 8b09816490c |
14 | 430a89952a4 |
15 | 21b11421a85 |
hex | 11c14e60920 |
1220121332000 has 48 divisors (see below), whose sum is σ = 2997838122552. Its totient is φ = 488048531200.
The previous prime is 1220121331999. The next prime is 1220121332051. The reversal of 1220121332000 is 2331210221.
It can be written as a sum of positive squares in 4 ways, for example, as 397116749584 + 823004582416 = 630172^2 + 907196^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1220121332000.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 152511167 + ... + 152519166.
Almost surely, 21220121332000 is an apocalyptic number.
1220121332000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1220121332000 is an abundant number, since it is smaller than the sum of its proper divisors (1777716790552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1220121332000 is an equidigital number, since it uses as much as digits as its factorization.
1220121332000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305030358 (or 305030340 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1220121332000 its reverse (2331210221), we get a palindrome (1222452542221).
The spelling of 1220121332000 in words is "one trillion, two hundred twenty billion, one hundred twenty-one million, three hundred thirty-two thousand".
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