Base | Representation |
---|---|
bin | 10110101110101010… |
… | …00000000110011111 |
3 | 1011111102020100000102 |
4 | 23113111000012133 |
5 | 144442322311341 |
6 | 5334502451315 |
7 | 611250614441 |
oct | 132725000637 |
9 | 34442210012 |
10 | 12202541471 |
11 | 51a202001a |
12 | 2446733b3b |
13 | 11c60cb853 |
14 | 83a8a2491 |
15 | 4b642cc9b |
hex | 2d754019f |
12202541471 has 2 divisors, whose sum is σ = 12202541472. Its totient is φ = 12202541470.
The previous prime is 12202541467. The next prime is 12202541473. The reversal of 12202541471 is 17414520221.
12202541471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12202541471 - 22 = 12202541467 is a prime.
It is a super-3 number, since 3×122025414713 (a number of 31 digits) contains 333 as substring.
Together with 12202541473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12202541473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101270735 + 6101270736.
It is an arithmetic number, because the mean of its divisors is an integer number (6101270736).
Almost surely, 212202541471 is an apocalyptic number.
12202541471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12202541471 is an equidigital number, since it uses as much as digits as its factorization.
12202541471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4480, while the sum is 29.
The spelling of 12202541471 in words is "twelve billion, two hundred two million, five hundred forty-one thousand, four hundred seventy-one".
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