Base | Representation |
---|---|
bin | 111000110100110001… |
… | …1100101101100100101 |
3 | 102122222111000101100201 |
4 | 1301221203211230211 |
5 | 3444404141141123 |
6 | 132020530510501 |
7 | 11550006032116 |
oct | 1615143455445 |
9 | 378874011321 |
10 | 122030021413 |
11 | 47830847273 |
12 | 1b797735431 |
13 | b679943381 |
14 | 5c98bb820d |
15 | 32932e85ad |
hex | 1c698e5b25 |
122030021413 has 2 divisors, whose sum is σ = 122030021414. Its totient is φ = 122030021412.
The previous prime is 122030021341. The next prime is 122030021441. The reversal of 122030021413 is 314120030221.
It is a happy number.
Together with previous prime (122030021341) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76617132804 + 45412888609 = 276798^2 + 213103^2 .
It is an emirp because it is prime and its reverse (314120030221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122030021413 - 225 = 121996466981 is a prime.
It is a super-2 number, since 2×1220300214132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122030021453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61015010706 + 61015010707.
It is an arithmetic number, because the mean of its divisors is an integer number (61015010707).
Almost surely, 2122030021413 is an apocalyptic number.
It is an amenable number.
122030021413 is a deficient number, since it is larger than the sum of its proper divisors (1).
122030021413 is an equidigital number, since it uses as much as digits as its factorization.
122030021413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 122030021413 its reverse (314120030221), we get a palindrome (436150051634).
The spelling of 122030021413 in words is "one hundred twenty-two billion, thirty million, twenty-one thousand, four hundred thirteen".
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