1221000113 has 2 divisors, whose sum is σ = 1221000114. Its totient is φ = 1221000112.

The previous prime is 1221000107. The next prime is 1221000119. The reversal of 1221000113 is 3110001221.

It is a balanced prime because it is at equal distance from previous prime (1221000107) and next prime (1221000119).

It can be written as a sum of positive squares in only one way, i.e., 1023232144 + 197767969 = 31988^2 + 14063^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1221000113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1221000094 and 1221000103.

It is not a weakly prime, because it can be changed into another prime (1221000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610500056 + 610500057.

It is an arithmetic number, because the mean of its divisors is an integer number (610500057).

Almost surely, 2^1221000113 is an apocalyptic number.

It is an amenable number.

1221000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221000113 is an equidigital number, since it uses as much as digits as its factorization.

1221000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1221000113 is about 34942.8120362400. The cubic root of 1221000113 is about 1068.8216314038.

Adding to 1221000113 its reverse (3110001221), we get a palindrome (4331001334).

The spelling of 1221000113 in words is "one billion, two hundred twenty-one million, one hundred thirteen", and thus it is an aban number.