Base | Representation |
---|---|
bin | 10001110001001010011… |
… | …101101001111101101111 |
3 | 11022201122222112202100002 |
4 | 101301022131221331233 |
5 | 130001122110000421 |
6 | 2332532344054515 |
7 | 154134004520132 |
oct | 21611235517557 |
9 | 4281588482302 |
10 | 1221020000111 |
11 | 430916a5a30a |
12 | 17878516443b |
13 | 8b1ac3b2cb2 |
14 | 43152086219 |
15 | 21b65288b0b |
hex | 11c4a769f6f |
1221020000111 has 2 divisors, whose sum is σ = 1221020000112. Its totient is φ = 1221020000110.
The previous prime is 1221020000023. The next prime is 1221020000119. The reversal of 1221020000111 is 1110000201221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221020000111 - 230 = 1219946258287 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1221020000092 and 1221020000101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221020000119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610510000055 + 610510000056.
It is an arithmetic number, because the mean of its divisors is an integer number (610510000056).
Almost surely, 21221020000111 is an apocalyptic number.
1221020000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221020000111 is an equidigital number, since it uses as much as digits as its factorization.
1221020000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 1221020000111 its reverse (1110000201221), we get a palindrome (2331020201332).
The spelling of 1221020000111 in words is "one trillion, two hundred twenty-one billion, twenty million, one hundred eleven", and thus it is an aban number.
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