Base | Representation |
---|---|
bin | 1011000110101110111101… |
… | …0100001110010011100010 |
3 | 1121020021221122102022200010 |
4 | 2301223233110032103202 |
5 | 3100023204400030310 |
6 | 41545201232305350 |
7 | 2400110626323024 |
oct | 261535724162342 |
9 | 47207848368603 |
10 | 12210312111330 |
11 | 3988400956963 |
12 | 14525349a2256 |
13 | 6a7573277888 |
14 | 302da746a014 |
15 | 162941855320 |
hex | b1aef50e4e2 |
12210312111330 has 64 divisors (see below), whose sum is σ = 29509429023360. Its totient is φ = 3233415952896.
The previous prime is 12210312111307. The next prime is 12210312111433. The reversal of 12210312111330 is 3311121301221.
It is a junction number, because it is equal to n+sod(n) for n = 12210312111297 and 12210312111306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 265681 + ... + 4948859.
It is an arithmetic number, because the mean of its divisors is an integer number (461084828490).
Almost surely, 212210312111330 is an apocalyptic number.
12210312111330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12210312111330 is an abundant number, since it is smaller than the sum of its proper divisors (17299116912030).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12210312111330 is a wasteful number, since it uses less digits than its factorization.
12210312111330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4683795.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12210312111330 its reverse (3311121301221), we get a palindrome (15521433412551).
The spelling of 12210312111330 in words is "twelve trillion, two hundred ten billion, three hundred twelve million, one hundred eleven thousand, three hundred thirty".
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