Base | Representation |
---|---|
bin | 1011000110110001111110… |
… | …0110000101011110000111 |
3 | 1121020101001002120000101022 |
4 | 2301230133212011132013 |
5 | 3100031334224200403 |
6 | 41545413445221355 |
7 | 2400136663161233 |
oct | 261543746053607 |
9 | 47211032500338 |
10 | 12211122100103 |
11 | 398878709a473 |
12 | 145272010185b |
13 | 6a7672017184 |
14 | 303042c755c3 |
15 | 16298ca01d38 |
hex | b1b1f985787 |
12211122100103 has 2 divisors, whose sum is σ = 12211122100104. Its totient is φ = 12211122100102.
The previous prime is 12211122100091. The next prime is 12211122100141. The reversal of 12211122100103 is 30100122111221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12211122100103 - 222 = 12211117905799 is a prime.
It is a super-3 number, since 3×122111221001033 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211122100183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105561050051 + 6105561050052.
It is an arithmetic number, because the mean of its divisors is an integer number (6105561050052).
Almost surely, 212211122100103 is an apocalyptic number.
12211122100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211122100103 is an equidigital number, since it uses as much as digits as its factorization.
12211122100103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12211122100103 its reverse (30100122111221), we get a palindrome (42311244211324).
The spelling of 12211122100103 in words is "twelve trillion, two hundred eleven billion, one hundred twenty-two million, one hundred thousand, one hundred three".
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