Base | Representation |
---|---|
bin | 111000110111001100… |
… | …1110000101101000111 |
3 | 102200012011000100100012 |
4 | 1301232121300231013 |
5 | 4000041000044033 |
6 | 132032553340435 |
7 | 11552014121534 |
oct | 1615631605507 |
9 | 380164010305 |
10 | 122111331143 |
11 | 4787273249a |
12 | 1b7baa0771b |
13 | b690741939 |
14 | 5ca5901d8b |
15 | 329a50a248 |
hex | 1c6e670b47 |
122111331143 has 4 divisors (see below), whose sum is σ = 129294350640. Its totient is φ = 114928311648.
The previous prime is 122111331101. The next prime is 122111331197. The reversal of 122111331143 is 341133111221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122111331143 - 212 = 122111327047 is a prime.
It is a super-2 number, since 2×1221113311432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122111331343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3591509723 + ... + 3591509756.
It is an arithmetic number, because the mean of its divisors is an integer number (32323587660).
Almost surely, 2122111331143 is an apocalyptic number.
122111331143 is a deficient number, since it is larger than the sum of its proper divisors (7183019497).
122111331143 is an equidigital number, since it uses as much as digits as its factorization.
122111331143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7183019496.
The product of its digits is 432, while the sum is 23.
Adding to 122111331143 its reverse (341133111221), we get a palindrome (463244442364).
The spelling of 122111331143 in words is "one hundred twenty-two billion, one hundred eleven million, three hundred thirty-one thousand, one hundred forty-three".
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