Base | Representation |
---|---|
bin | 1011000110110010010100… |
… | …0001100110101011100101 |
3 | 1121020101021102222101002022 |
4 | 2301230211001212223211 |
5 | 3100032031034400401 |
6 | 41545430501552525 |
7 | 2400142150415006 |
oct | 261544501465345 |
9 | 47211242871068 |
10 | 12211213200101 |
11 | 3988823562223 |
12 | 1452746715745 |
13 | 6a7687b629b6 |
14 | 303050dcb1ad |
15 | 1629959e971b |
hex | b1b25066ae5 |
12211213200101 has 4 divisors (see below), whose sum is σ = 12211223205792. Its totient is φ = 12211203194412.
The previous prime is 12211213200097. The next prime is 12211213200143. The reversal of 12211213200101 is 10100231211221.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 12211213200101 - 22 = 12211213200097 is a prime.
It is a super-2 number, since 2×122112132001012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12211213200101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12211213200301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2868755 + ... + 5714208.
It is an arithmetic number, because the mean of its divisors is an integer number (3052805801448).
Almost surely, 212211213200101 is an apocalyptic number.
It is an amenable number.
12211213200101 is a deficient number, since it is larger than the sum of its proper divisors (10005691).
12211213200101 is an equidigital number, since it uses as much as digits as its factorization.
12211213200101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10005690.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12211213200101 its reverse (10100231211221), we get a palindrome (22311444411322).
It can be divided in two parts, 12211 and 213200101, that added together give a palindrome (213212312).
The spelling of 12211213200101 in words is "twelve trillion, two hundred eleven billion, two hundred thirteen million, two hundred thousand, one hundred one".
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