Base | Representation |
---|---|
bin | 11011110000111110100110… |
… | …000011000001000011110011 |
3 | 121000100212222222221112000022 |
4 | 123300332212003001003303 |
5 | 112001144411224014303 |
6 | 1111413534353314055 |
7 | 34502242000305302 |
oct | 3360764603010363 |
9 | 530325888845008 |
10 | 122113001001203 |
11 | 359aa918649793 |
12 | 11842398b6592b |
13 | 531a28bb330a4 |
14 | 222242d4ca439 |
15 | e1b68ce1b438 |
hex | 6f0fa60c10f3 |
122113001001203 has 2 divisors, whose sum is σ = 122113001001204. Its totient is φ = 122113001001202.
The previous prime is 122113001001197. The next prime is 122113001001353. The reversal of 122113001001203 is 302100100311221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122113001001203 is a prime.
It is not a weakly prime, because it can be changed into another prime (122113001007203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61056500500601 + 61056500500602.
It is an arithmetic number, because the mean of its divisors is an integer number (61056500500602).
Almost surely, 2122113001001203 is an apocalyptic number.
122113001001203 is a deficient number, since it is larger than the sum of its proper divisors (1).
122113001001203 is an equidigital number, since it uses as much as digits as its factorization.
122113001001203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 122113001001203 its reverse (302100100311221), we get a palindrome (424213101312424).
The spelling of 122113001001203 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one million, one thousand, two hundred three".
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