Base | Representation |
---|---|
bin | 10110101111110011… |
… | …00101010100101001 |
3 | 1011112002021112112100 |
4 | 23113321211110221 |
5 | 200002301143423 |
6 | 5335444204013 |
7 | 611425254540 |
oct | 132771452451 |
9 | 34462245470 |
10 | 12212131113 |
11 | 51a747a946 |
12 | 2449999609 |
13 | 11c80a86b0 |
14 | 83bc7b157 |
15 | 4b71c4343 |
hex | 2d7e65529 |
12212131113 has 48 divisors (see below), whose sum is σ = 21733246080. Its totient is φ = 6434802432.
The previous prime is 12212131093. The next prime is 12212131147. The reversal of 12212131113 is 31113121221.
It is not a de Polignac number, because 12212131113 - 25 = 12212131081 is a prime.
It is a super-3 number, since 3×122121311133 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (12212111113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 827245 + ... + 841877.
It is an arithmetic number, because the mean of its divisors is an integer number (452775960).
Almost surely, 212212131113 is an apocalyptic number.
12212131113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12212131113 is a deficient number, since it is larger than the sum of its proper divisors (9521114967).
12212131113 is a wasteful number, since it uses less digits than its factorization.
12212131113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15678 (or 15675 counting only the distinct ones).
The product of its digits is 72, while the sum is 18.
Adding to 12212131113 its reverse (31113121221), we get a palindrome (43325252334).
The spelling of 12212131113 in words is "twelve billion, two hundred twelve million, one hundred thirty-one thousand, one hundred thirteen".
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