Base | Representation |
---|---|
bin | 10110101111110011… |
… | …00101101010111100 |
3 | 1011112002021121111012 |
4 | 23113321211222330 |
5 | 200002301220130 |
6 | 5335444214352 |
7 | 611425261646 |
oct | 132771455274 |
9 | 34462247435 |
10 | 12212132540 |
11 | 51a7480a23 |
12 | 244999a3b8 |
13 | 11c80a923a |
14 | 83bc7b896 |
15 | 4b71c4995 |
hex | 2d7e65abc |
12212132540 has 24 divisors (see below), whose sum is σ = 25666602192. Its totient is φ = 4880829440.
The previous prime is 12212132539. The next prime is 12212132549. The reversal of 12212132540 is 4523121221.
It is a super-3 number, since 3×122121325403 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12212132549) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 226526 + ... + 275205.
It is an arithmetic number, because the mean of its divisors is an integer number (1069441758).
Almost surely, 212212132540 is an apocalyptic number.
12212132540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12212132540 is an abundant number, since it is smaller than the sum of its proper divisors (13454469652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12212132540 is a wasteful number, since it uses less digits than its factorization.
12212132540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 502957 (or 502955 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 12212132540 its reverse (4523121221), we get a palindrome (16735253761).
The spelling of 12212132540 in words is "twelve billion, two hundred twelve million, one hundred thirty-two thousand, five hundred forty".
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