Base | Representation |
---|---|
bin | 10110101111110011… |
… | …11111111010000011 |
3 | 1011112002111001220022 |
4 | 23113321333322003 |
5 | 200002313140003 |
6 | 5335450404055 |
7 | 611426220155 |
oct | 132771777203 |
9 | 34462431808 |
10 | 12212240003 |
11 | 51a7544737 |
12 | 2449a3062b |
13 | 11c8116122 |
14 | 83bca8ad5 |
15 | 4b71e6738 |
hex | 2d7e7fe83 |
12212240003 has 4 divisors (see below), whose sum is σ = 12930607080. Its totient is φ = 11493872928.
The previous prime is 12212239997. The next prime is 12212240009. The reversal of 12212240003 is 30004221221.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30004221221 = 13 ⋅2308017017.
It is an interprime number because it is at equal distance from previous prime (12212239997) and next prime (12212240009).
It is a cyclic number.
It is not a de Polignac number, because 12212240003 - 28 = 12212239747 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 718367059 = 12212240003 / (1 + 2 + 2 + 1 + 2 + 2 + 4 + 0 + 0 + 0 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12212240009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359183513 + ... + 359183546.
It is an arithmetic number, because the mean of its divisors is an integer number (3232651770).
Almost surely, 212212240003 is an apocalyptic number.
12212240003 is a deficient number, since it is larger than the sum of its proper divisors (718367077).
12212240003 is an equidigital number, since it uses as much as digits as its factorization.
12212240003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 718367076.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 12212240003 its reverse (30004221221), we get a palindrome (42216461224).
The spelling of 12212240003 in words is "twelve billion, two hundred twelve million, two hundred forty thousand, three".
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