Base | Representation |
---|---|
bin | 10110101111110011… |
… | …11111111011101111 |
3 | 1011112002111002001022 |
4 | 23113321333323233 |
5 | 200002313140421 |
6 | 5335450404355 |
7 | 611426220401 |
oct | 132771777357 |
9 | 34462432038 |
10 | 12212240111 |
11 | 51a7544825 |
12 | 2449a306bb |
13 | 11c81161a6 |
14 | 83bca8b71 |
15 | 4b71e67ab |
hex | 2d7e7feef |
12212240111 has 2 divisors, whose sum is σ = 12212240112. Its totient is φ = 12212240110.
The previous prime is 12212240041. The next prime is 12212240113. The reversal of 12212240111 is 11104221221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12212240111 is a prime.
Together with 12212240113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12212240111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212240113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106120055 + 6106120056.
It is an arithmetic number, because the mean of its divisors is an integer number (6106120056).
Almost surely, 212212240111 is an apocalyptic number.
12212240111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212240111 is an equidigital number, since it uses as much as digits as its factorization.
12212240111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 12212240111 its reverse (11104221221), we get a palindrome (23316461332).
The spelling of 12212240111 in words is "twelve billion, two hundred twelve million, two hundred forty thousand, one hundred eleven".
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