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122143314341 = 712237714477
BaseRepresentation
bin111000111000001001…
…1110001000110100101
3102200021101012021001002
41301300103301012211
54000122142024331
6132040055043045
711552553020156
oct1616023610645
9380241167032
10122143314341
1147889797994
121b809670485
13b69725c4c9
145ca9c6992d
15329d2269cb
hex1c704f11a5

122143314341 has 8 divisors (see below), whose sum is σ = 124419101184. Its totient is φ = 119882957040.

The previous prime is 122143314313. The next prime is 122143314407. The reversal of 122143314341 is 143413341221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 122143314341 - 214 = 122143297957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122143314311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3841406 + ... + 3873071.

It is an arithmetic number, because the mean of its divisors is an integer number (15552387648).

Almost surely, 2122143314341 is an apocalyptic number.

It is an amenable number.

122143314341 is a deficient number, since it is larger than the sum of its proper divisors (2275786843).

122143314341 is an equidigital number, since it uses as much as digits as its factorization.

122143314341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7714771.

The product of its digits is 6912, while the sum is 29.

Adding to 122143314341 its reverse (143413341221), we get a palindrome (265556655562).

The spelling of 122143314341 in words is "one hundred twenty-two billion, one hundred forty-three million, three hundred fourteen thousand, three hundred forty-one".

Divisors: 1 71 223 15833 7714477 547727867 1720328371 122143314341